(6/y)=(2/3y)

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Solution for (6/y)=(2/3y) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

6/y = (2/3)*y // - (2/3)*y

6/y-((2/3)*y) = 0

(-2/3)*y+6/y = 0

6*y^-1-2/3*y^1 = 0

(6*y^0-2/3*y^2)/(y^1) = 0 // * y^2

y^1*(6*y^0-2/3*y^2) = 0

y^1

(-2/3)*y^2+6 = 0

(-2/3)*y^2+6 = 0

DELTA = 0^2-(4*6*(-2/3))

DELTA = 16

DELTA > 0

y = (16^(1/2)+0)/(2*(-2/3)) or y = (0-16^(1/2))/(2*(-2/3))

y = -3 or y = 3

y in { -3, 3} 

y in { -3, 3 }

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