(60+2x)(20+2x)=1716

Solution for (60+2x)(20+2x)=1716 equation:

(60+2x)(20+2x)=1716

We move all terms to the left:

(60+2x)(20+2x)-(1716)=0

We add all the numbers together, and all the variables

(2x+60)(2x+20)-1716=0

We multiply parentheses ..

(+4x^2+40x+120x+1200)-1716=0

We get rid of parentheses

4x^2+40x+120x+1200-1716=0

We add all the numbers together, and all the variables

4x^2+160x-516=0

a = 4; b = 160; c = -516;
Δ = b2-4ac
Δ = 1602-4·4·(-516)
Δ = 33856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{33856}=184$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-184}{2*4}=\frac{-344}{8}
=-43
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+184}{2*4}=\frac{24}{8}
=3
$