(60+n)/3=(84+n)/15

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Solution for (60+n)/3=(84+n)/15 equation:



(60+n)/3=(84+n)/15
We move all terms to the left:
(60+n)/3-((84+n)/15)=0
We add all the numbers together, and all the variables
(n+60)/3-((n+84)/15)=0
We calculate fractions
n/()+(-((n+84)*3)/()=0
We calculate terms in parentheses: +(-((n+84)*3)/(), so:
-((n+84)*3)/(
We multiply all the terms by the denominator
-((n+84)*3)
We calculate terms in parentheses: -((n+84)*3), so:
(n+84)*3
We multiply parentheses
3n+252
Back to the equation:
-(3n+252)
We get rid of parentheses
-3n-252
Back to the equation:
+(-3n-252)
We get rid of parentheses
n/()-3n-252=0
We multiply all the terms by the denominator
n-3n*()-252*()=0
We add all the numbers together, and all the variables
n-3n*()=0

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