(60-10x)/4+12=22

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Solution for (60-10x)/4+12=22 equation: 



(60-10x)/4+12=22

We move all terms to the left:

(60-10x)/4+12-(22)=0

We add all the numbers together, and all the variables

(-10x+60)/4+12-22=0

We add all the numbers together, and all the variables

(-10x+60)/4-10=0

We multiply all the terms by the denominator


(-10x+60)-10*4=0

We add all the numbers together, and all the variables

(-10x+60)-40=0

We get rid of parentheses

-10x+60-40=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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