(60-2x)*(40-2x)=2380,04

Solution for (60-2x)*(40-2x)=2380,04 equation:

(60-2x)(40-2x)=2380.04

We move all terms to the left:

(60-2x)(40-2x)-(2380.04)=0

We add all the numbers together, and all the variables

(-2x+60)(-2x+40)-(2380.04)=0

We add all the numbers together, and all the variables

(-2x+60)(-2x+40)-2380.04=0

We multiply parentheses ..

(+4x^2-80x-120x+2400)-2380.04=0

We get rid of parentheses

4x^2-80x-120x+2400-2380.04=0

We add all the numbers together, and all the variables

4x^2-200x+19.96=0

a = 4; b = -200; c = +19.96;
Δ = b2-4ac
Δ = -2002-4·4·19.96
Δ = 39680.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-\sqrt{39680.64}}{2*4}=\frac{200-\sqrt{39680.64}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+\sqrt{39680.64}}{2*4}=\frac{200+\sqrt{39680.64}}{8}
$