(60-2x)=(3x+45)

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Solution for (60-2x)=(3x+45) equation: 



(60-2x)=(3x+45)

We move all terms to the left:

(60-2x)-((3x+45))=0

We add all the numbers together, and all the variables

(-2x+60)-((3x+45))=0

We get rid of parentheses

-2x-((3x+45))+60=0



We calculate terms in parentheses: -((3x+45)), so:

(3x+45)

We get rid of parentheses

3x+45

Back to the equation:

-(3x+45)



We get rid of parentheses

-2x-3x-45+60=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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