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(60/x-0.5)(x+4)=60
We move all terms to the left:
(60/x-0.5)(x+4)-(60)=0
Domain of the equation: x-0.5)(x+4)!=0We multiply parentheses ..
x∈R
(+60x^2+240x-0.5x-2)-60=0
We get rid of parentheses
60x^2+240x-0.5x-2-60=0
We add all the numbers together, and all the variables
60x^2+239.5x-62=0
a = 60; b = 239.5; c = -62;
Δ = b2-4ac
Δ = 239.52-4·60·(-62)
Δ = 72240.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(239.5)-\sqrt{72240.25}}{2*60}=\frac{-239.5-\sqrt{72240.25}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(239.5)+\sqrt{72240.25}}{2*60}=\frac{-239.5+\sqrt{72240.25}}{120} $
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