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(60/y)=2y
We move all terms to the left:
(60/y)-(2y)=0
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+60/y)-2y=0
We add all the numbers together, and all the variables
-2y+(+60/y)=0
We get rid of parentheses
-2y+60/y=0
We multiply all the terms by the denominator
-2y*y+60=0
Wy multiply elements
-2y^2+60=0
a = -2; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-2)·60
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*-2}=\frac{0-4\sqrt{30}}{-4} =-\frac{4\sqrt{30}}{-4} =-\frac{\sqrt{30}}{-1} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*-2}=\frac{0+4\sqrt{30}}{-4} =\frac{4\sqrt{30}}{-4} =\frac{\sqrt{30}}{-1} $
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