(63)+(2x-4)+(6x+22)=180

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Solution for (63)+(2x-4)+(6x+22)=180 equation: 



(63)+(2x-4)+(6x+22)=180

We move all terms to the left:

(63)+(2x-4)+(6x+22)-(180)=0

We add all the numbers together, and all the variables

(2x-4)+(6x+22)-117=0

We get rid of parentheses

2x+6x-4+22-117=0

We add all the numbers together, and all the variables

8x-99=0

We move all terms containing x to the left, all other terms to the right

8x=99

x=99/8

x=12+3/8

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