(63)+(3x-4)+(6x+22)=180

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Solution for (63)+(3x-4)+(6x+22)=180 equation: 



(63)+(3x-4)+(6x+22)=180

We move all terms to the left:

(63)+(3x-4)+(6x+22)-(180)=0

We add all the numbers together, and all the variables

(3x-4)+(6x+22)-117=0

We get rid of parentheses

3x+6x-4+22-117=0

We add all the numbers together, and all the variables

9x-99=0

We move all terms containing x to the left, all other terms to the right

9x=99

x=99/9

x=11

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