(63/x)+(126/2x)-2x=67

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Solution for (63/x)+(126/2x)-2x=67 equation: 



(63/x)+(126/2x)-2x=67

We move all terms to the left:

(63/x)+(126/2x)-2x-(67)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+63/x)+(+126/2x)-2x-67=0

We add all the numbers together, and all the variables

-2x+(+63/x)+(+126/2x)-67=0

We get rid of parentheses

-2x+63/x+126/2x-67=0

We calculate fractions


-2x+126x/2x^2+126x/2x^2-67=0

We multiply all the terms by the denominator


-2x*2x^2+126x+126x-67*2x^2=0

We add all the numbers together, and all the variables

252x-2x*2x^2-67*2x^2=0

Wy multiply elements

-4x^3-134x^2+252x=0

We do not support expression: x^3

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