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(63/x)=(9/5)
We move all terms to the left:
(63/x)-((9/5))=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+63/x)-((+9/5))=0
We get rid of parentheses
63/x-((+9/5))=0
We calculate fractions
()/5x^2+(-((+9*x)/5x^2=0
We add all the numbers together, and all the variables
()/5x^2+(-((+9x)/5x^2=0
We multiply all the terms by the denominator
(-((+9x)+()=0
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