(64-3x)+(12x+2)+(180-(186-11x)=180

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Solution for (64-3x)+(12x+2)+(180-(186-11x)=180 equation: 



(64-3x)+(12x+2)+(180-(186-11x)=180

We move all terms to the left:

(64-3x)+(12x+2)+(180-(186-11x)-(180)=0

We add all the numbers together, and all the variables

(-3x+64)+(12x+2)+(180-(-11x+186)-180=0

We get rid of parentheses

-3x+12x+(180-(-11x+186)-180+64+2=0

We add all the numbers together, and all the variables

9x+(180-(-11x+186)-180+64+2=0

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