(65-x)+20+(3x+7)+(x-72)=180

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Solution for (65-x)+20+(3x+7)+(x-72)=180 equation: 



(65-x)+20+(3x+7)+(x-72)=180

We move all terms to the left:

(65-x)+20+(3x+7)+(x-72)-(180)=0

We add all the numbers together, and all the variables

(-1x+65)+(3x+7)+(x-72)+20-180=0

We add all the numbers together, and all the variables

(-1x+65)+(3x+7)+(x-72)-160=0

We get rid of parentheses

-1x+3x+x+65+7-72-160=0

We add all the numbers together, and all the variables

3x-160=0

We move all terms containing x to the left, all other terms to the right

3x=160

x=160/3

x=53+1/3

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