(68+12)+23=68+(12+n)

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Solution for (68+12)+23=68+(12+n) equation: 



(68+12)+23=68+(12+n)

We move all terms to the left:

(68+12)+23-(68+(12+n))=0

We add all the numbers together, and all the variables

-(68+(n+12))+23+80=0

We add all the numbers together, and all the variables

-(68+(n+12))+103=0



We calculate terms in parentheses: -(68+(n+12)), so:

68+(n+12)

determiningTheFunctionDomain
(n+12)+68

We get rid of parentheses

n+12+68

We add all the numbers together, and all the variables

n+80

Back to the equation:

-(n+80)



We get rid of parentheses

-n-80+103=0

We add all the numbers together, and all the variables

-1n+23=0

We move all terms containing n to the left, all other terms to the right

-n=-23

n=-23/-1

n=+23

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