(68+4a)/(12+2a)=5

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Solution for (68+4a)/(12+2a)=5 equation: 



(68+4a)/(12+2a)=5

We move all terms to the left:

(68+4a)/(12+2a)-(5)=0



Domain of the equation: (12+2a)!=0

We move all terms containing a to the left, all other terms to the right

2a!=-12

a!=-12/2

a!=-6

a∈R



We add all the numbers together, and all the variables

(4a+68)/(2a+12)-5=0

We multiply all the terms by the denominator


(4a+68)-5*(2a+12)=0

We multiply parentheses

(4a+68)-10a-60=0

We get rid of parentheses

4a-10a+68-60=0

We add all the numbers together, and all the variables

-6a+8=0

We move all terms containing a to the left, all other terms to the right

-6a=-8

a=-8/-6

a=1+1/3

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