(68-x)+(83-2x)=180

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Solution for (68-x)+(83-2x)=180 equation: 



(68-x)+(83-2x)=180

We move all terms to the left:

(68-x)+(83-2x)-(180)=0

We add all the numbers together, and all the variables

(-1x+68)+(-2x+83)-180=0

We get rid of parentheses

-1x-2x+68+83-180=0

We add all the numbers together, and all the variables

-3x-29=0

We move all terms containing x to the left, all other terms to the right

-3x=29

x=29/-3

x=-9+2/3

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