(6a+10)(3a=55)

Solution for (6a+10)(3a=55) equation:

(6a+10)(3a=55)

We move all terms to the left:

(6a+10)(3a-(55))=0

We multiply parentheses ..

(+18a^2-330a+30a-550)=0

We get rid of parentheses

18a^2-330a+30a-550=0

We add all the numbers together, and all the variables

18a^2-300a-550=0

a = 18; b = -300; c = -550;
Δ = b2-4ac
Δ = -3002-4·18·(-550)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-360}{2*18}=\frac{-60}{36}
=-1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+360}{2*18}=\frac{660}{36}
=18+1/3
$