(6a+2)(3a-6)=0

Solution for (6a+2)(3a-6)=0 equation:

(6a+2)(3a-6)=0

We multiply parentheses ..

(+18a^2-36a+6a-12)=0

We get rid of parentheses

18a^2-36a+6a-12=0

We add all the numbers together, and all the variables

18a^2-30a-12=0

a = 18; b = -30; c = -12;
Δ = b2-4ac
Δ = -302-4·18·(-12)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-42}{2*18}=\frac{-12}{36}
=-1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+42}{2*18}=\frac{72}{36}
=2
$