(6a+2)(8a+7)=0

Solution for (6a+2)(8a+7)=0 equation:

(6a+2)(8a+7)=0

We multiply parentheses ..

(+48a^2+42a+16a+14)=0

We get rid of parentheses

48a^2+42a+16a+14=0

We add all the numbers together, and all the variables

48a^2+58a+14=0

a = 48; b = 58; c = +14;
Δ = b2-4ac
Δ = 582-4·48·14
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-26}{2*48}=\frac{-84}{96}
=-7/8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+26}{2*48}=\frac{-32}{96}
=-1/3
$