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(6a+5)(a-6)=0
We multiply parentheses ..
(+6a^2-36a+5a-30)=0
We get rid of parentheses
6a^2-36a+5a-30=0
We add all the numbers together, and all the variables
6a^2-31a-30=0
a = 6; b = -31; c = -30;
Δ = b2-4ac
Δ = -312-4·6·(-30)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-41}{2*6}=\frac{-10}{12} =-5/6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+41}{2*6}=\frac{72}{12} =6 $
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