(6a-3)/5+(7a-12)+a=6a+3

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Solution for (6a-3)/5+(7a-12)+a=6a+3 equation:



(6a-3)/5+(7a-12)+a=6a+3
We move all terms to the left:
(6a-3)/5+(7a-12)+a-(6a+3)=0
We add all the numbers together, and all the variables
a+(6a-3)/5+(7a-12)-(6a+3)=0
We get rid of parentheses
a+(6a-3)/5+7a-6a-12-3=0
We multiply all the terms by the denominator
a*5+(6a-3)+7a*5-6a*5-12*5-3*5=0
We add all the numbers together, and all the variables
a*5+(6a-3)+7a*5-6a*5-75=0
Wy multiply elements
5a+(6a-3)+35a-30a-75=0
We get rid of parentheses
5a+6a+35a-30a-3-75=0
We add all the numbers together, and all the variables
16a-78=0
We move all terms containing a to the left, all other terms to the right
16a=78
a=78/16
a=4+7/8

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