(6c+4)-(3c+1)=11

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Solution for (6c+4)-(3c+1)=11 equation:


Simplifying
(6c + 4) + -1(3c + 1) = 11

Reorder the terms:
(4 + 6c) + -1(3c + 1) = 11

Remove parenthesis around (4 + 6c)
4 + 6c + -1(3c + 1) = 11

Reorder the terms:
4 + 6c + -1(1 + 3c) = 11
4 + 6c + (1 * -1 + 3c * -1) = 11
4 + 6c + (-1 + -3c) = 11

Reorder the terms:
4 + -1 + 6c + -3c = 11

Combine like terms: 4 + -1 = 3
3 + 6c + -3c = 11

Combine like terms: 6c + -3c = 3c
3 + 3c = 11

Solving
3 + 3c = 11

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3c = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 3c = 11 + -3
3c = 11 + -3

Combine like terms: 11 + -3 = 8
3c = 8

Divide each side by '3'.
c = 2.666666667

Simplifying
c = 2.666666667

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