(6c+5)(c+2)=0

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Solution for (6c+5)(c+2)=0 equation:


Simplifying
(6c + 5)(c + 2) = 0

Reorder the terms:
(5 + 6c)(c + 2) = 0

Reorder the terms:
(5 + 6c)(2 + c) = 0

Multiply (5 + 6c) * (2 + c)
(5(2 + c) + 6c * (2 + c)) = 0
((2 * 5 + c * 5) + 6c * (2 + c)) = 0
((10 + 5c) + 6c * (2 + c)) = 0
(10 + 5c + (2 * 6c + c * 6c)) = 0
(10 + 5c + (12c + 6c2)) = 0

Combine like terms: 5c + 12c = 17c
(10 + 17c + 6c2) = 0

Solving
10 + 17c + 6c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + c)(5 + 6c) = 0

Subproblem 1

Set the factor '(2 + c)' equal to zero and attempt to solve: Simplifying 2 + c = 0 Solving 2 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + c = 0 + -2 c = 0 + -2 Combine like terms: 0 + -2 = -2 c = -2 Simplifying c = -2

Subproblem 2

Set the factor '(5 + 6c)' equal to zero and attempt to solve: Simplifying 5 + 6c = 0 Solving 5 + 6c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 6c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 6c = 0 + -5 6c = 0 + -5 Combine like terms: 0 + -5 = -5 6c = -5 Divide each side by '6'. c = -0.8333333333 Simplifying c = -0.8333333333

Solution

c = {-2, -0.8333333333}

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