(6c-40)-(c-3);c=-7

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Solution for (6c-40)-(c-3);c=-7 equation: 



(6c-40)-(c-3)c=-7

We move all terms to the left:

(6c-40)-(c-3)c-(-7)=0

We add all the numbers together, and all the variables

(6c-40)-(c-3)c+7=0

We multiply parentheses

-c^2+(6c-40)+3c+7=0

We get rid of parentheses

-c^2+6c+3c-40+7=0

We add all the numbers together, and all the variables

-1c^2+9c-33=0

a = -1; b = 9; c = -33;
Δ = b2-4ac
Δ = 92-4·(-1)·(-33)
Δ = -51
Delta is less than zero, so there is no solution for the equation

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