(6c-5)=4(7c-8)+3

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Solution for (6c-5)=4(7c-8)+3 equation: 



(6c-5)=4(7c-8)+3

We move all terms to the left:

(6c-5)-(4(7c-8)+3)=0

We get rid of parentheses

6c-(4(7c-8)+3)-5=0



We calculate terms in parentheses: -(4(7c-8)+3), so:

4(7c-8)+3

We multiply parentheses

28c-32+3

We add all the numbers together, and all the variables

28c-29

Back to the equation:

-(28c-29)



We get rid of parentheses

6c-28c+29-5=0

We add all the numbers together, and all the variables

-22c+24=0

We move all terms containing c to the left, all other terms to the right

-22c=-24

c=-24/-22

c=1+1/11

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