(6d-5)(6d-7)=0

Solution for (6d-5)(6d-7)=0 equation:

(6d-5)(6d-7)=0

We multiply parentheses ..

(+36d^2-42d-30d+35)=0

We get rid of parentheses

36d^2-42d-30d+35=0

We add all the numbers together, and all the variables

36d^2-72d+35=0

a = 36; b = -72; c = +35;
Δ = b2-4ac
Δ = -722-4·36·35
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-12}{2*36}=\frac{60}{72}
=5/6
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+12}{2*36}=\frac{84}{72}
=1+1/6
$