(6g-1)(7g-1)=0

Solution for (6g-1)(7g-1)=0 equation:

(6g-1)(7g-1)=0

We multiply parentheses ..

(+42g^2-6g-7g+1)=0

We get rid of parentheses

42g^2-6g-7g+1=0

We add all the numbers together, and all the variables

42g^2-13g+1=0

a = 42; b = -13; c = +1;
Δ = b2-4ac
Δ = -132-4·42·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-1}{2*42}=\frac{12}{84}
=1/7
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+1}{2*42}=\frac{14}{84}
=1/6
$