(6g-7)(7g+4)=0

Solution for (6g-7)(7g+4)=0 equation:

(6g-7)(7g+4)=0

We multiply parentheses ..

(+42g^2+24g-49g-28)=0

We get rid of parentheses

42g^2+24g-49g-28=0

We add all the numbers together, and all the variables

42g^2-25g-28=0

a = 42; b = -25; c = -28;
Δ = b2-4ac
Δ = -252-4·42·(-28)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-73}{2*42}=\frac{-48}{84}
=-4/7
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+73}{2*42}=\frac{98}{84}
=1+1/6
$