(6h+5)(h-1)=0

Solution for (6h+5)(h-1)=0 equation:

(6h+5)(h-1)=0

We multiply parentheses ..

(+6h^2-6h+5h-5)=0

We get rid of parentheses

6h^2-6h+5h-5=0

We add all the numbers together, and all the variables

6h^2-1h-5=0

a = 6; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·6·(-5)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*6}=\frac{-10}{12}
=-5/6
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*6}=\frac{12}{12}
=1
$