(6i)/(-2i)

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Solution for (6i)/(-2i) equation: 


D( i )

-2*i = 0

-2*i = 0

-2*i = 0

-2*i = 0 // : -2

i = 0

i in (-oo:0) U (0:+oo)

(6*i)/(-2*i) = 0

-3 = 0

i belongs to the empty set

i belongs to the empty set

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