(6j+7)(-6j+5)=0

Solution for (6j+7)(-6j+5)=0 equation:

(6j+7)(-6j+5)=0

We multiply parentheses ..

(-36j^2+30j-42j+35)=0

We get rid of parentheses

-36j^2+30j-42j+35=0

We add all the numbers together, and all the variables

-36j^2-12j+35=0

a = -36; b = -12; c = +35;
Δ = b2-4ac
Δ = -122-4·(-36)·35
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-72}{2*-36}=\frac{-60}{-72}
=5/6
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+72}{2*-36}=\frac{84}{-72}
=-1+1/6
$