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(6m-17)m=5
We move all terms to the left:
(6m-17)m-(5)=0
We multiply parentheses
6m^2-17m-5=0
a = 6; b = -17; c = -5;
Δ = b2-4ac
Δ = -172-4·6·(-5)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{409}}{2*6}=\frac{17-\sqrt{409}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{409}}{2*6}=\frac{17+\sqrt{409}}{12} $
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