(6m-2)+(8m+4)+(10m-20)=180

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Solution for (6m-2)+(8m+4)+(10m-20)=180 equation: 



(6m-2)+(8m+4)+(10m-20)=180

We move all terms to the left:

(6m-2)+(8m+4)+(10m-20)-(180)=0

We get rid of parentheses

6m+8m+10m-2+4-20-180=0

We add all the numbers together, and all the variables

24m-198=0

We move all terms containing m to the left, all other terms to the right

24m=198

m=198/24

m=8+1/4

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