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(6m-30)m=11
We move all terms to the left:
(6m-30)m-(11)=0
We multiply parentheses
6m^2-30m-11=0
a = 6; b = -30; c = -11;
Δ = b2-4ac
Δ = -302-4·6·(-11)
Δ = 1164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1164}=\sqrt{4*291}=\sqrt{4}*\sqrt{291}=2\sqrt{291}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{291}}{2*6}=\frac{30-2\sqrt{291}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{291}}{2*6}=\frac{30+2\sqrt{291}}{12} $
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