(6m-5)=2(m-7)+11

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Solution for (6m-5)=2(m-7)+11 equation: 



(6m-5)=2(m-7)+11

We move all terms to the left:

(6m-5)-(2(m-7)+11)=0

We get rid of parentheses

6m-(2(m-7)+11)-5=0



We calculate terms in parentheses: -(2(m-7)+11), so:

2(m-7)+11

We multiply parentheses

2m-14+11

We add all the numbers together, and all the variables

2m-3

Back to the equation:

-(2m-3)



We get rid of parentheses

6m-2m+3-5=0

We add all the numbers together, and all the variables

4m-2=0

We move all terms containing m to the left, all other terms to the right

4m=2

m=2/4

m=1/2

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