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(6n+4)(5n+7)=180
We move all terms to the left:
(6n+4)(5n+7)-(180)=0
We multiply parentheses ..
(+30n^2+42n+20n+28)-180=0
We get rid of parentheses
30n^2+42n+20n+28-180=0
We add all the numbers together, and all the variables
30n^2+62n-152=0
a = 30; b = 62; c = -152;
Δ = b2-4ac
Δ = 622-4·30·(-152)
Δ = 22084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22084}=\sqrt{4*5521}=\sqrt{4}*\sqrt{5521}=2\sqrt{5521}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{5521}}{2*30}=\frac{-62-2\sqrt{5521}}{60} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{5521}}{2*30}=\frac{-62+2\sqrt{5521}}{60} $
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