(6n+5)(n+2)=0

Solution for (6n+5)(n+2)=0 equation:

(6n+5)(n+2)=0

We multiply parentheses ..

(+6n^2+12n+5n+10)=0

We get rid of parentheses

6n^2+12n+5n+10=0

We add all the numbers together, and all the variables

6n^2+17n+10=0

a = 6; b = 17; c = +10;
Δ = b2-4ac
Δ = 172-4·6·10
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*6}=\frac{-24}{12}
=-2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*6}=\frac{-10}{12}
=-5/6
$