(6n-20)+(5n-11)=180-(171-n)

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Solution for (6n-20)+(5n-11)=180-(171-n) equation: 



(6n-20)+(5n-11)=180-(171-n)

We move all terms to the left:

(6n-20)+(5n-11)-(180-(171-n))=0

We add all the numbers together, and all the variables

(6n-20)+(5n-11)-(180-(-1n+171))=0

We get rid of parentheses

6n+5n-(180-(-1n+171))-20-11=0



We calculate terms in parentheses: -(180-(-1n+171)), so:

180-(-1n+171)

determiningTheFunctionDomain
-(-1n+171)+180

We get rid of parentheses

1n-171+180

We add all the numbers together, and all the variables

n+9

Back to the equation:

-(n+9)



We add all the numbers together, and all the variables

11n-(n+9)-31=0

We get rid of parentheses

11n-n-9-31=0

We add all the numbers together, and all the variables

10n-40=0

We move all terms containing n to the left, all other terms to the right

10n=40

n=40/10

n=4

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