(6n-4)/8=(2n+12)/4

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Solution for (6n-4)/8=(2n+12)/4 equation: 



(6n-4)/8=(2n+12)/4

We move all terms to the left:

(6n-4)/8-((2n+12)/4)=0

We calculate fractions


6n/()+(-((2n+12)*8)/()=0



We calculate terms in parentheses: +(-((2n+12)*8)/(), so:

-((2n+12)*8)/(

We multiply all the terms by the denominator


-((2n+12)*8)



We calculate terms in parentheses: -((2n+12)*8), so:

(2n+12)*8

We multiply parentheses

16n+96

Back to the equation:

-(16n+96)



We get rid of parentheses

-16n-96

Back to the equation:

+(-16n-96)



We get rid of parentheses

6n/()-16n-96=0

We multiply all the terms by the denominator


6n-16n*()-96*()=0

We add all the numbers together, and all the variables

6n-16n*()=0

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