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(6n-6)(7n-8)=0
We multiply parentheses ..
(+42n^2-48n-42n+48)=0
We get rid of parentheses
42n^2-48n-42n+48=0
We add all the numbers together, and all the variables
42n^2-90n+48=0
a = 42; b = -90; c = +48;
Δ = b2-4ac
Δ = -902-4·42·48
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-6}{2*42}=\frac{84}{84} =1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+6}{2*42}=\frac{96}{84} =1+1/7 $
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