(6p+2)(5p-4)=0

Solution for (6p+2)(5p-4)=0 equation:

(6p+2)(5p-4)=0

We multiply parentheses ..

(+30p^2-24p+10p-8)=0

We get rid of parentheses

30p^2-24p+10p-8=0

We add all the numbers together, and all the variables

30p^2-14p-8=0

a = 30; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·30·(-8)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-34}{2*30}=\frac{-20}{60}
=-1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+34}{2*30}=\frac{48}{60}
=4/5
$