(6p-5)(p-2)=0

Solution for (6p-5)(p-2)=0 equation:

(6p-5)(p-2)=0

We multiply parentheses ..

(+6p^2-12p-5p+10)=0

We get rid of parentheses

6p^2-12p-5p+10=0

We add all the numbers together, and all the variables

6p^2-17p+10=0

a = 6; b = -17; c = +10;
Δ = b2-4ac
Δ = -172-4·6·10
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*6}=\frac{10}{12}
=5/6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*6}=\frac{24}{12}
=2
$