(6r+13)(r+112)=0

Solution for (6r+13)(r+112)=0 equation:

(6r+13)(r+112)=0

We multiply parentheses ..

(+6r^2+672r+13r+1456)=0

We get rid of parentheses

6r^2+672r+13r+1456=0

We add all the numbers together, and all the variables

6r^2+685r+1456=0

a = 6; b = 685; c = +1456;
Δ = b2-4ac
Δ = 6852-4·6·1456
Δ = 434281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{434281}=659$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(685)-659}{2*6}=\frac{-1344}{12}
=-112
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(685)+659}{2*6}=\frac{-26}{12}
=-2+1/6
$