(6s+2+)(4s-2)=180

Solution for (6s+2+)(4s-2)=180 equation:

(6s+2+)(4s-2)=180

We move all terms to the left:

(6s+2+)(4s-2)-(180)=0

We add all the numbers together, and all the variables

(+6s)(4s-2)-180=0

We multiply parentheses ..

(+24s^2-12s)-180=0

We get rid of parentheses

24s^2-12s-180=0

a = 24; b = -12; c = -180;
Δ = b2-4ac
Δ = -122-4·24·(-180)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-132}{2*24}=\frac{-120}{48}
=-2+1/2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+132}{2*24}=\frac{144}{48}
=3
$