(6s+5)(s-2)=0

Solution for (6s+5)(s-2)=0 equation:

(6s+5)(s-2)=0

We multiply parentheses ..

(+6s^2-12s+5s-10)=0

We get rid of parentheses

6s^2-12s+5s-10=0

We add all the numbers together, and all the variables

6s^2-7s-10=0

a = 6; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·6·(-10)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*6}=\frac{-10}{12}
=-5/6
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*6}=\frac{24}{12}
=2
$