(6t-4)/(3t-2)=-7/2

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Solution for (6t-4)/(3t-2)=-7/2 equation:



(6t-4)/(3t-2)=-7/2
We move all terms to the left:
(6t-4)/(3t-2)-(-7/2)=0
Domain of the equation: (3t-2)!=0
We move all terms containing t to the left, all other terms to the right
3t!=2
t!=2/3
t!=2/3
t∈R
We get rid of parentheses
(6t-4)/(3t-2)+7/2=0
We calculate fractions
(12t-8)/(6t-4)+(21t-14)/(6t-4)=0
We multiply all the terms by the denominator
(12t-8)+(21t-14)=0
We get rid of parentheses
12t+21t-8-14=0
We add all the numbers together, and all the variables
33t-22=0
We move all terms containing t to the left, all other terms to the right
33t=22
t=22/33
t=2/3
Równanie nie ma rozwiązania

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