(6v)(2v=3)

Solution for (6v)(2v=3) equation:

(6v)(2v=3)

We move all terms to the left:

(6v)(2v-(3))=0

We multiply parentheses

12v^2-18v=0

a = 12; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·12·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*12}=\frac{0}{24}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*12}=\frac{36}{24}
=1+1/2
$