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(6v+6)=(3v+12)
We move all terms to the left:
(6v+6)-((3v+12))=0
We get rid of parentheses
6v-((3v+12))+6=0
We calculate terms in parentheses: -((3v+12)), so:We get rid of parentheses
(3v+12)
We get rid of parentheses
3v+12
Back to the equation:
-(3v+12)
6v-3v-12+6=0
We add all the numbers together, and all the variables
3v-6=0
We move all terms containing v to the left, all other terms to the right
3v=6
v=6/3
v=2
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