(6v-5)(v-4)=0

Solution for (6v-5)(v-4)=0 equation:

(6v-5)(v-4)=0

We multiply parentheses ..

(+6v^2-24v-5v+20)=0

We get rid of parentheses

6v^2-24v-5v+20=0

We add all the numbers together, and all the variables

6v^2-29v+20=0

a = 6; b = -29; c = +20;
Δ = b2-4ac
Δ = -292-4·6·20
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-19}{2*6}=\frac{10}{12}
=5/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+19}{2*6}=\frac{48}{12}
=4
$